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FULL_PDE_LAW.txt
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FIGURE 8
=>
...........................................................................................
//SORT 20201025 19:47 AM D8+
来继续持续绝对专注论证肽增公式1.0 BY USING ENGLISH FOR - 4 BITS DIUQ WAY
PDE SWAP LAW
S = I
S = Q
C = D
PDE MASK LAW
I = !D
D = !I
U = !Q
Q = !U
PDE COMPS LAW
I = ++D
U = ++I
Q = ++U
DD= ++Q
VECS PDE LAW
V= U + Q
E= I + U
C= I + D
S= I + Q
AOPM PDE LAW
A= V + S
O= E + S
P= E + C
M= C + S
SO :
I 增加 !-> D ~-> I !-> D ~-> I
D 减少 !-> I ~-> U !-> Q ~-> DD (肽增)
U 改变 !-> I ~-> U !-> I ~-> U
Q 查找 !-> U ~-> Q !-> U ~-> Q
THEN WE FIND?
PDE SWAP NEW LAW
D = DD
V 感知->U + Q !-> QU ~-> QQ !-> UU ~-> UQ = V
E 执行->I + U !-> DQ ~-> DDD !-> III ~-> IIU = I + E (肽增)
C 控制->I + D !-> DI ~-> DU !-> IQ ~-> UDD = U + D (肽展) = U + D + D (肽增)
THEN WE FIND
U = E
I = U
THEN 1
A= V + S = U + Q + I + Q = UQIQ !-> QUDU ~-> QUDQ !-> UQIU ~-> UQIQ = A
O= E + S = I + U + I + Q = IUIQ !-> DQDU ~-> DQDQ !-> IUIU ~-> IUIQ = O
P= E + C = I + U + I + D = IUID !-> DQDI ~-> DQDU !-> IUIQ ~-> IUIDD = P + D (肽增)
M= C + S = I + D + I + Q = IDIQ !-> DIDU ~-> DIDQ !-> IDIU ~-> IDIQ = M
THEN 2
A= V + S = U + Q + I + Q = UQI !-> QUD ~-> QUI !-> UQD ~-> UQI = A
O= E + S = I + U + I + Q = IUQ !-> DQU ~-> DQQ !-> IUU ~-> IUQ = O
P= E + C = I + U + I + D = IUD !-> DQI ~-> DQU !-> IUQ ~-> IUDD = P + D (肽增)
M= C + S = I + D + I + Q = IDQ !-> DIU ~-> DIQ !-> IDU ~-> IDQ = M
IT SEEMS 4BIT-PDE IS A GOOD WAY~
FIGURE 9
ABOVE ALL, WE FIND PDE LAW LIST AS BELOW:
PDE MASK LAW
I = D!
D = I!
U = Q!
Q = U!
PDE COMP'S LAW
DD = ++Q
I = ++D
U = ++I
Q = ++U
PDE (肽减) LAW
C = D (肽减)
S = I (肽减)
S = Q (肽减)
PDE (肽增) LAW
D = DD (肽增)
U = E (肽增)
I = U (肽增)
E = I + E (肽增)
P = P + D (肽增)
C = U + D + D(肽增)
PDE (肽展) LAW
A = V + S (肽展)
A = U + Q + I (肽展)
O = E + S (肽展)
O = I + U + Q (肽展)
P = E + C (肽展)
P = I + U + D (肽展)
M = C + S (肽展)
M = I + D + Q (肽展)
V = U + Q (肽展)
E = I + U (肽展)
E = D + U (肽展)
C = I + D (肽展)
S = I + Q (肽展)
FLASH A NEW NAME 可以推断:
A 分析(LTA 变胸腺腺苷) O 操作(UCLA 尿胞变腺苷) P 处理(UCLG 尿胞变鸟苷) M 管理(GA 鸟腺苷)
V 感知(LT 变胸腺嘌呤) E 执行(UCL 尿胞变嘌呤) C 控制(G 鸟嘌呤) S 静态(A 腺嘌呤)
I 增加(U 尿嘧啶) D 减少(C 胞嘧啶) U 改变(L 变嘧啶) Q 感应(T 胸腺嘧啶)
U 改变(L 变嘧啶)定义为 L the first char of luo YG and liang BY, Named by yaoguangluo 20201025
END
2020-10-25 21:30 PM, D8+, YAOGUANGLUO LIUYANG
今天发现 A = U + Q + I (肽展)与 O = I + U + Q (肽展) 出现逆对称 引起了我的注意
于是 现在 我们增加4BIT LAW演化如下
A = U + Q + I + Q
O = I + U + I + Q
P = I + U + I + D
M = I + D + I + Q